Math test
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Rμν−12gμν R+gμνΛ=8πGc4Tμν R_{\mu \nu} - {1 \over 2}g_{\mu \nu}\,R + g_{\mu \nu} \Lambda = {8 \pi G \over c^4} T_{\mu \nu} Rμν−21gμνR+gμνΛ=c48πGTμν -
1+q2(1−q)+q6(1−q)(1−q2)+⋯=∏j=0∞1(1−q5j+2)(1−q5j+3),for ∣q∣<1. 1 + \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots = \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}, \quad\quad \text{for $|q|<1$}. 1+(1−q)q2+(1−q)(1−q2)q6+⋯=j=0∏∞(1−q5j+2)(1−q5j+3)1,for ∣q∣<1. -
@admin 我认为是Physics test
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@admin 刚刚试了一下感觉效果特别好，谢谢管理员大大嘿嘿
